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Let ⊕\oplus⊕ and ⊙\odot⊙ be two operators on numbers ppp and qqq such that
p⊙q=p−qp \odot q = p - qp⊙q=p−q, and p⊕q=p×qp \oplus q = p \times qp⊕q=p×q
Then, (9⊙(6⊕7))⊙(7⊕(6⊙5))=(9 \odot (6 \oplus 7)) \odot (7 \oplus (6 \odot 5)) =(9⊙(6⊕7))⊙(7⊕(6⊙5))= ?
40
-26
-33
-40
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